“I never teach my pupils; I only attempt to provide the conditions in which they can learn.” ~ ALBERT EINSTEIN
Alternative way.....The gradient of CB can be found as (4-2)/(3-7)=-1/2. Since the chord is perpendicular to CB, by the relationship of m1xm2=-1, the gradient of the chord is 2.
To: Life is Good我用的方法的确太长了。其实只需看看那个图就知道要求一条垂直线就可以了。罪过罪过。谢谢提醒。
Alternative way.....The gradient of CB can be found as (4-2)/(3-7)=-1/2. Since the chord is perpendicular to CB, by the relationship of m1xm2=-1, the gradient of the chord is 2.
ReplyDeleteTo: Life is Good
ReplyDelete我用的方法的确太长了。其实只需看看那个图就知道要求一条垂直线就可以了。罪过罪过。谢谢提醒。